制冷空调系统仿真原理与技术
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文禾斗2018-04-17"rpm=5400" "input RPM of compressor"T_e_f=T_e*1.8+32 "convert C to F"T_c_f=T_c*1.8+32 "convert C to F"Mass_flow_f=-2.671976131+0.195957777*rpm+0.004176833*T_e_f*rpm-0.047105055*T_e_f^2+8.07928E-7*T_e_f*T_c_f*rpm+4.33615E-5*T_e_f^2*rpm+0.000689089*T_e_f^3-1.36275*10^(-6)*T_c_f^2*rpm-2.06261E-08*T_e_f*rpm^2+2.8982E-08*T_c_f*rpm^2-2.62007E-10*rpm^3[lbm/h] "mass flow rate of R410A , lbm/hr"Power=-1945.747177+ 45.4888449*T_c_f + 1.20698896*rpm +0.520695827*T_e_f*T_c_f-0.018367942*T_e_f*rpm-0.604449805*T_e_f^2-0.482203109*T_c_f^2-0.000112383*rpm^2+6.85998E-05*T_e_f*T_c_f*rpm+0.004529094*T_e_f^2*T_c_f-0.000892496*T_e_f^3-0.003121958*T_e_f*T_c_f^2 +9.13092E-05*T_c_f^2*rpm+0.001964748*T_c_f^3+2.11448E-06*T_e_f*rpm^2+1.48053E-08*rpm^3[W] "input power of compressor , W"C...